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29x^2-3x-2000=0
a = 29; b = -3; c = -2000;
Δ = b2-4ac
Δ = -32-4·29·(-2000)
Δ = 232009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{232009}}{2*29}=\frac{3-\sqrt{232009}}{58} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{232009}}{2*29}=\frac{3+\sqrt{232009}}{58} $
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